128x^2=50

Solution for 128x^2=50 equation:

128x^2=50

We move all terms to the left:

128x^2-(50)=0

a = 128; b = 0; c = -50;
Δ = b2-4ac
Δ = 02-4·128·(-50)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*128}=\frac{-160}{256}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*128}=\frac{160}{256}
=5/8
$